There is a more efficient algorithm (in terms of the number of multiplications and additions used) for evaluating polynomials than the conventional algorithm described in the previous exercise. It is called Horner's method. This pseudocode shows how to use this method to find the value of an x^n an-1 x^n-1 ⋯ a1 x a0 at x=cprocedure Horner (c, a0, a1, a2, …, an:. real numbers ) y:=anfor i:=1 to n y:=y * c an-ireturn y{y=an c^n an-1 c^n-1 ⋯ a1 c a0}a) Evaluate 3 x^2 x 1 at x=2 by working through e

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